Etext 8.46

8.46-A random sample of 10 miniature tootsie rolls was taken from a bag. Each piece was weighed on a rattling need scale. The results in grams were: 3.087, 3.131, 3.241, 3.270, 3.353, 3.400, 3.411, 3.437, 3.477 (a) piss a 90% sanction interval for the true mean weight. sample distribution mean = 3.3048 Sample commonplace deviation = 0.13199 Standard misapprehension: 1.645*0.13199/Sqrt(10) = 0.06866 90% CI- 3.3048-0.06866 < u < 3.3048 + 0.06866 90% CI- 3.23614 < u < 3.37346 (b) What sample surface would be necessary to hypothesize the true weight with an mistake rate of +/- 0.03 grams with 90% authorization? n = [1.645*0.13199/0.03]^2 = 7.42^2 = 52.38 Rounding up to shed light on for n = 53 (c) Discuss the actors which business leader cause play in the weight of the tootsie rolls during manufacturing. Factors such as the amount of ingredients used to deplume out the tootsie rolls along with the humidness and temperature control. Also the machine tolerances may be a factor in causing variation during manufacturing. 8.

62- In 1992, the FAA conducted 86,991 pre-employment drug tests on the job applicants who were to be assiduous in safety and trade protection related jobs, and found that 1,143 were absolute. (a) Construct a 95% assurance interval for the population proportionality of positive drug tests. p-hat = 1143/86991 = 0.013139... E = 1.96*sqrt[(0.013139)*(0.98686)/86991] = 0.002393 CI is (0.013139 0.002393, 0.013139 + 0.00239) (b) Why is the atomic number 7 speculation non a line of work, despite the very small care for of p? The normality assumption was not a problem because the random sample was very large.If you insufficiency to get a enough essay, order it on our website: Ordercustompaper.com

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